A 10 F, 20 F, 22 F, and 100 F capacitor are in parallel. What is the total capacitance?

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Answer 1 · 2015-01-30T16:45:16

The answer is: $152 F$ $152F$ .

The difference of potential ( $DeltaV$ ) across the two capacitors is the same (the one of the generator);
Q is divided between the capacitors;
If $C_1 and C_2 and C_3 and...$ are different, so $Q_1 and Q_2 and Q_3 and...$ are different.

So:

$C_(eq)=Q/V=(Q_1+Q_2+Q_3+...)/V=Q_1/V+Q_2/V+Q_3/V+...=C_1+C_2+C_3+...$

So:

To find the equivalent capacitor of two or more capacitors in parallel it is necessary to use this formula:

$C_(eq)=C_1+C_2+C_3+...$

In this case:

$C_(eq)=10F+20F+22F+100F=152F$ .