# Four 0.15 µF capacitors are in parallel. What is the total capacitance?

$0.60 \mu F$
Capacitors are in parallel, individual capacitances are summed to find the total: $C = {C}_{1} + {C}_{2} + {C}_{3} + {C}_{4}$
So $C = 4 \cdot 0.15 \mu F = 0.60 \mu F$