# A 21.5L sample of gas at 107kPa has a temperature of 27.20C. What is the pressure of the gas if it is transferred to a 32.6L container at 44.10C?

Aug 4, 2018

${P}_{2} \approx \text{74.5 kPa}$

#### Explanation:

Use

$P V = n R T$

where $n$ and $R$ stay constant during the transfer.

$n R = \frac{P V}{T}$

so

$\frac{{P}_{1} {V}_{1}}{{T}_{1}} = \frac{{P}_{2} {V}_{2}}{{T}_{2}}$

or

${P}_{2} = \frac{{P}_{1} {V}_{1} {T}_{2}}{{V}_{2} {T}_{1}}$

Don't forget that

T = θ+273.15

So

${P}_{2} = \left(\text{107 kPa" * "21.5 L" * (44.10 + 273.15)\ "K")/("32.6 L" * (27.20 + 273.15) \ "K}\right)$

${P}_{2} \approx \text{74.5 kPa}$