# A 30-60-90 triangle has a hypotenuse with a length of 10. What is the length of the longer leg?

Because it is a right triangle and if $x$ the longer leg we have that
$\sin {60}^{o} = \frac{x}{10} \implies x = \sin {60}^{0} \cdot 10 = \frac{\sqrt{3}}{2} \cdot 10 = 5 \cdot \sqrt{3}$