A 50.0 mL urine sample has a mass of 50.7 g. What is the specific gravity of the urine?
The specific gravity of a substance,
So right from the start, the fact that specific gravity is a ratio of two densities should let you know that you're looking for a unitless quantity.
In your case, the specific gravity of urine will be
#"SG"_ "urine" = rho_"urine"/rho_"water"#
Use the mass and volume of the sample to calculate its density, which is essentially the mass of *one unit of volume of a given substance
#1 color(red)(cancel(color(black)("mL"))) * "50.7 g"/(50.0color(red)(cancel(color(Black)("mL")))) = "1.014 g"#
This means that urine has a density of
Now, water has a maximum density of
#"SG"_ "urine" =(1.014 color(red)(cancel(color(black)("g mL"^(-1)))))/(0.999975color(red)(cancel(color(black)("g mL"^(-1))))) = color(green)(bar(ul(|color(white)(a/a)color(black)(1.01)color(white)(a/a)|))) #
The answer is rounded to three sig figs.