Question

A 55.0-g aluminum block initially at 27.5 C absorbs 725 J of heat. What is the final temperature of the aluminum?

Answer 1

The final temperature of aluminum is 42.1 °C.

Explanation:

`Q=mc∆T`

This means that the amount of energy produced is equal to the mass of the system multiplied by its change of temperature and multiplied by its specific heat.

LET'S PUT IN WHAT WE KNOW!!!

`Q ="725 J"`

`m="55.0 g"`

`c = "0.900 J/(°C·g)"`

`∆T = "final temperature - initial temperature"`

`∆T = (x-27.5) " °C"`

We solve for `∆T`.

`"725 J" = "55.0 g"*"0.900 J/(°C·g)"(x-27.5) " °C"`

NOW IT'S JUST BASIC ALGREBRA

`725 = 49.5x-1361`

`2086=49.5x`

`42.1 = x`

The final temperature is 42.1 °C.