A ball is shot out of a cannon. The height of the ball, h in meters, as a function of the time, t in seconds, since it was shot is given by the equation #h= -5t^2 +30t +1#. What is the height of the ball after 1 second?

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Answer 1 · 2016-03-03T12:16:49

#h="26 m"#

Since this is a function of #t#, time, the height when #t=1# can be found by plugging in #1# for #t#.

#h=-5(1)^2+30(1)+1#

#h=-5+30+1#

#h="26 m"#