# A ball of pure titanium has a mass of 16.19 g and a diameter of 19.0 mm. What is the density of titanium?

Jan 22, 2017

$\text{Density}$ $=$ $\text{Mass"/"Volume}$

${\rho}_{\text{titanium}} \cong 4 \cdot g \cdot c {m}^{-} 3$

#### Explanation:

So all we have to do is calculate this quotient, and remember the formula for the volume of a sphere, $= \frac{4}{3} \pi {r}^{3}$

Now since $r = \frac{1.9}{2} \cdot c m$ (density is usually quoted as $g \cdot m L$ or $g \cdot c {m}^{-} 3$, at least by chemists it is...........)

${\rho}_{\text{titanium}} = \frac{m}{V} = \frac{16.19 \cdot g}{\frac{4}{3} \pi {\left(\frac{1.9}{2} \cdot c m\right)}^{3}} \ge 4 \cdot g \cdot c {m}^{-} 3$

Would this float on water? Why or why not?