A ball rolls with a speed of 2.0m/s across a level table that is 1.0m above the floor. Upon reaching the edge of the table, it follows a parabolic path to the floor. How far along the floor is the landing spot from the table?

Mar 8, 2016

We need to consider vertical and horizontal components.

Explanation:

If we consider the vertical component, we can determine how long the ball is in free fall. We can use:
$s = u t + \frac{1}{2} a {t}^{2}$
S=1m
And u, initial velocity in vertical direction, is 0m/s
And we can take acceleration as 9.81 $m {s}^{-} 2$
$1 = \frac{1}{2} \cdot 9.8 \cdot {t}^{2}$

So t= 0.45s

In the horizontal direction, there is no acceleration so we can simply use $v e l o c i t y = \frac{S}{t}$
Hence distance along the floor from the table is $2 \times 0.45 = 0.9 m$