A ball with a mass of #360 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #24 (kg)/s^2# and was compressed by #5/3 m# when the ball was released. How high will the ball go?

1 Answer
May 19, 2017

Answer:

9.448m

Explanation:

The mass has to be put in kg:
#360g=0.36kg#

We will use the conservation of energy.

The energy put by the spring:
#U_("spring")=1/2kx^2#
The energy for the gravitation:
#U_g=mgy#

If we apply the conservation of energy to this situation:
#U_("spring")=U_g#

We put the three equations together:
#1/2kx^2=mgy#

We isolate the height (y):
#=>(kx^2)/(2mg)=y#

We take all the values of our situation and put them in there:
#=>y=((24)(5/3)^2)/((2)(0.36)(9.8)#
#=9.448m#