# A block of metal has a width of 32 cm, a length of 17.1 cm, and height of 38 cm. Its mass is 1.1kg. What is the density of the metal?

$\text{Density} , \rho$ $=$ $\text{Mass"/"Volume}$
And thus, $\rho$ $=$ $\frac{1.1 \cdot k g \times {10}^{3} \cdot g \cdot k {g}^{-} 1}{\left(32 \times 17.1 \times 38\right) \cdot c {m}^{3}}$
This gives the answer in $g \cdot c {m}^{-} 3$ rather than $k g \cdot c {m}^{-} 3$.