A box with an initial speed of #2 m/s# is moving up a ramp. The ramp has a kinetic friction coefficient of #1/2 # and an incline of #(2 pi )/3 #. How far along the ramp will the box go?

1 Answer
Jul 4, 2017

Answer:

0.331m (3sf)

Explanation:

Resolving perpendicular to the slope:
R=mgcos#((2pi)/3)#
R=#(-mg)/2#

F=#mu#R

F=#(-mg)/4#

Resolving parallel to the slope:
0 - (F + mgsin#((2pi)/3)#) = ma (mass cancels)

Using suvat:
s = #(v^2-u^2)/(2a)#
s = 0.331m