Question

A box with an initial speed of `2 m/s` is moving up a ramp. The ramp has a kinetic friction coefficient of `1/2` and an incline of `(2 pi )/3`. How far along the ramp will the box go?

Answer 1

0.331m (3sf)

Explanation:

Resolving perpendicular to the slope:
R=mgcos`((2pi)/3)`
R=`(-mg)/2`

F=`mu`R

F=`(-mg)/4`

Resolving parallel to the slope:
0 - (F + mgsin`((2pi)/3)`) = ma (mass cancels)

Using suvat:
s = `(v^2-u^2)/(2a)`
s = 0.331m