Question

A box with an initial speed of `2 m/s` is moving up a ramp. The ramp has a kinetic friction coefficient of `3/4` and an incline of `(5 pi )/8`. How far along the ramp will the box go?

Answer 1

The distance travelled is `1/3m`

Explanation:

We have to find first the retardation of rhe object.

We have already got the retardation of the object.
Hence we have to put the formula
`v^2=u^2-2as` where v,u,a & s are respectively final velocity, initial velocity, retardation and displacement.
Here,`u=2,v=0,a=6ms^-2`
So,
`2^2=2×6×s`
`s=1/3`