A box with an initial speed of #2 m/s# is moving up a ramp. The ramp has a kinetic friction coefficient of #3/4 # and an incline of #(5 pi )/8 #. How far along the ramp will the box go?

1 Answer
Jul 11, 2017

Answer:

The distance travelled is #1/3m#

Explanation:

We have to find first the retardation of rhe object.
my notebook.
We have already got the retardation of the object.
Hence we have to put the formula
#v^2=u^2-2as# where v,u,a & s are respectively final velocity, initial velocity, retardation and displacement.
Here,#u=2,v=0,a=6ms^-2#
So,
#2^2=2×6×s#
#s=1/3#