A charge of 16 C is passing through points A and B on a circuit. If the charge's electric potential changes from 48 J to 12 J, what is the voltage between points A and B?

Apr 14, 2016

${V}_{\text{AB}} = - 2 , 25 V$

Explanation:

$q = 16 C$
${E}_{A} = 48 J \text{ the electric potential energy at the point of A}$

${E}_{B} = 12 J \text{ the electric potential energy at the point of B}$

${E}_{B} - {E}_{A} = 12 - 48 = - 36 J \text{ work between the A and B}$

$W = q \cdot {V}_{\text{AB}}$

$- 36 = 16 \cdot {V}_{\text{AB}}$

${V}_{\text{AB}} = - \frac{36}{16}$

${V}_{\text{AB}} = - 2 , 25 V$