A charge of 16 C is passing through points A and B on a circuit. If the charge's electric potential changes from 54 J to 12 J, what is the voltage between points A and B?

Jun 20, 2017

The voltage is $= 2.625 V$

Explanation:

The charge is $Q = 16 C$

The variation in the charge electric potential is

$\Delta W = 54 - 12 = 42 J$

The voltage is $\Delta V = \frac{\Delta W}{Q} = \frac{42}{16} = 2.625 V$