# A charge of 16 C is passing through points A and B on a circuit. If the charge's electric potential changes from 38 J to 12 J, what is the voltage between points A and B?

Feb 9, 2016

${V}_{A B} = - 1 , 625 \text{ V}$
$\Delta W = q \cdot \left({V}_{B} - {V}_{A}\right)$
$12 - 38 = 16 \cdot {V}_{A B}$
$- 26 = 16 \cdot {V}_{A B}$
${V}_{A B} = \frac{- 26}{16}$
${V}_{A B} = - 1 , 625 \text{ V}$