# A charge of 2 C is passing through points A and B on a circuit. If the charge's electric potential changes from 21 J to 5 J, what is the voltage between points A and B?

Feb 24, 2017

The voltage is $= 8 V$

#### Explanation:

The potential difference =work done/charge

The work done is the electric potential

Work done $= \left(21 - 5\right) J$

Charge $= 2 C$

Voltage $= \frac{21 - 5}{2} = \frac{16}{2} = 8 V$