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A charge of $2 C$ $2 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $25 J$ $25 J$ to $19 J$ $19 J$ , what is the voltage between points A and B?

1 Answer

Mar 26, 2016

$\frac{25 - 19}{2} (\frac{J}{C}) = 3 V$ $(25-19)/2(J/C)=3V$

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