Question

A charge of `2 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `17 J` to `8 J`, what is the voltage between points A and B?

Answer 1

`V_"AB"=-4,5 " V"`

Explanation:

`Delta W=q(V_B-V_A)`
`Delta W=W_2-W_1`

`V_B-V_A=V_"AB"`
`Delta W=q*V_"AB"`

`Delta W=8-17=-9 J`
`-9=2*V_"AB"`

`V_"AB"=-4,5 " V"`