# A charge of 25 C is passing through points A and B on a circuit. If the charge's electric potential changes from 38 J to 14 J, what is the voltage between points A and B?

$0.96 V$
put the formula of $V = \frac{J}{C}$ then subtract $38 - 14 = 24 J$ now put this in the formula $J = \frac{24}{25}$
$J = 0.96 V$