A charge of #4 C# is passing through points A and B on a circuit. If the charge's electric potential changes from #27 J# to #11 J#, what is the voltage between points A and B?

1 Answer

Answer:

#DeltaV=-4" "#volts

Explanation:

The formula for the Difference in Electric Potential in volts

#DeltaV=V_B-V_A=(EPE_B-EPE_A)/q_0

Where #V_B=#Electric potential at point B
#V_A=#Electric potential at point A

Electric Potential Energy final
#EPE_B=11" "#Joule

Electric Potential Energy initial
#EPE_A=27" "#Joule

Test charge
#q_0=4" "#Coulomb

#DeltaV=V_B-V_A=(EPE_B-EPE_A)/q_0=(11-27)/4=-4" "#volts