# A charge of 4 C is passing through points A and B on a circuit. If the charge's electric potential changes from 27 J to 15 J, what is the voltage between points A and B?

Jul 5, 2018

$3$ volts

#### Explanation:

Using the definition, voltage is the difference of electric potential between two points per unit charge passing through it. We can express it as an equation in the form of:

$V = \frac{B - A}{C}$

where:

• $B$ is the electric potential of the second point

• $A$ is the electric potential of the first point

• $C$ is the charge passing through in coulombs

So, we get:

$V = \left(27 \setminus \text{J"-15 \ "J")/(4 \ "C}\right)$

$= \left(12 \setminus \text{J")/(4 \ "C}\right)$

$= 3 \setminus \text{V}$