A charge of 4 C is passing through points A and B on a circuit. If the charge's electric potential changes from 27 J to 18 J, what is the voltage between points A and B?

Feb 1, 2016

$\frac{9}{4} V$

Explanation:

Voltage is just another name for electrical potential difference - that is, the change in electric potential between two points per coulomb.

$1 V = 1 \frac{J}{C}$

If the $4 C$ charge's electric potential drops from $27 J$ to $18 J$ then the voltage is
$V = \frac{27 - 18}{4} = \frac{9}{4} V$