# A charge of 4 C is passing through points A and B on a circuit. If the charge's electric potential changes from 38 J to 13 J, what is the voltage between points A and B?

Dec 18, 2017

#### Answer:

The voltage is $= 6.25 V$

#### Explanation:

The charge is $Q = 4 C$

The change in the charge electric potential is

$\Delta E = 38 - 13 = 25 J$

Apply the equation

$U = \frac{\Delta E}{Q}$

The voltage is

$U = \frac{25}{4} = 6.25 V$