# A charge of 4 C is passing through points A and B on a circuit. If the charge's electric potential changes from 38 J to 14 J, what is the voltage between points A and B?

Jan 19, 2016

$6 \text{V}$

#### Explanation:

The question is badly worded as electric potential is measured in volts, not Joules.

I will assume that the change in potential energy, i.e the work done in moving a charge of $4 C$ through a potential difference of $V$ volts is $38 - 14 = 24 \text{J}$

$\therefore 4 \times V = 24$

$V = \frac{24}{4} = 6 V$

Unit check: $V = \frac{J}{C}$