A charge of #5# #C# is passing through points A and B on a circuit. If the charge's electric potential changes from #28# #J# to #15# #J#, what is the voltage between points A and B?

1 Answer
Apr 12, 2018

Answer:

Point A is at a voltage #2.6# #V# higher than point B. We would express this as #-2.6# #V# from A to B.

Explanation:

One volt is defined as one joule per coulomb, which we can write as #V=U/C# where #V# is the voltage difference, #U# is the electric potential in joule and #Q# is the charge in coulomb.

In this case we're interested in the potential difference, so

#V=(DeltaU)/Q=(15-28)/5=(-13)/5=-2.6# #V#

That is, point A is at a voltage #2.6# #V# higher than point B.