Question

A charge of `6 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `28 J` to `9 J`, what is the voltage between points A and B?

Answer 1

The voltage is `=3.17V`

Explanation:

The potential difference between the points `A` and `B` is `=U`

Voltage =Energy)/Charge

`U=(DeltaE)/Q`

`DeltaE=28-9=19J`

The charge is `Q=6C`

`1 V=(1J)/C`

`U=19/6=3.17V`