# A charge of 6 C is passing through points A and B on a circuit. If the charge's electric potential changes from 33 J to 12 J, what is the voltage between points A and B?

Mar 30, 2016

${V}_{\text{AB"=-3,50" }} V$

#### Explanation:

$\Delta W = {W}_{2} - {W}_{1} = 12 - 33 = - 21 J$

${V}_{\text{AB}} = {V}_{B} - {V}_{A}$

$\Delta W = q \cdot {V}_{\text{AB}}$

$- 21 = 6 \cdot {V}_{\text{AB}}$

${V}_{\text{AB}} = - \frac{21}{6}$

${V}_{\text{AB"=-3,50" }} V$