A charge of 6 C is passing through points A and B on a circuit. If the charge's electric potential changes from 24 J to 18 J, what is the voltage between points A and B?

Jul 10, 2016

The voltage drop is 1 volt.

Explanation:

The relationship here is very simple:
$E = V Q$

Since we know the voltage drop...
$E = 24 - 18 = 6$

And the charge...
$V Q = 6 V$
$6 = 6 V$
$V = 1$