# A charge of 8 C is passing through points A and B on a circuit. If the charge's electric potential changes from 64 J to 8 J, what is the voltage between points A and B?

Jan 26, 2016

Electric potential is $\left(\text{Energy")/("Charge}\right)$, and the potential difference is the change in potential.
$V = \frac{E}{Q}$
$\Delta V = \frac{\Delta E}{Q}$
$\Delta V = \frac{8 J - 64 J}{8 C}$
$\Delta V = - 7 V$