# A charge of 8 C is passing through points A and B on a circuit. If the charge's electric potential changes from 28 J to 15 J, what is the voltage between points A and B?

$\frac{13}{8} V$
By definition, voltage is the electric potential difference per unit charge. We can say, $\Delta V = \frac{\Delta E}{C}$
Hence, $\text{the voltage} = \frac{\left(28 - 15\right) J}{8 C} = \frac{13}{8} V$