# A charge of 8 C is passing through points A and B on a circuit. If the charge's electric potential changes from 32 J to 4 J, what is the voltage between points A and B?

May 24, 2017

#### Answer:

The voltage is $= 3.5 V$

#### Explanation:

The potential difference between the points $A$ and $B$ is $= U$

Voltage =(Energy)/Charge

$U = \frac{\Delta E}{Q}$

$\Delta E = 32 - 4 = 28 J$

The charge is $Q = 8 C$

$1 V = \frac{1 J}{C}$

$U = \frac{28}{8} = 3.5 V$