Question

A charge of `9 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `17 J` to `1 J`, what is the voltage between points A and B?

Answer 1

`16/9` Volts

Explanation:

Voltage = Potential Difference = `"Work Done"/"Charge"`
Change in Electric Potential = `delta E` = Work Done by the charge.

So,

Voltage = `(17 - 1)/9` Volts
`= 16/9` Volts