# A charge of 9 C is passing through points A and B on a circuit. If the charge's electric potential changes from 17 J to 1 J, what is the voltage between points A and B?

$\frac{16}{9}$ Volts

#### Explanation:

Voltage = Potential Difference = $\text{Work Done"/"Charge}$
Change in Electric Potential = $\delta E$ = Work Done by the charge.

So,

Voltage = $\frac{17 - 1}{9}$ Volts
$= \frac{16}{9}$ Volts