A circle's center is at $(2 ,4 )$ and it passes through $(8 ,3 )$ . What is the length of an arc covering $( pi ) /3$ radians on the circle?

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Answer 1 · 2016-08-14T07:46:34

Given that coordinate of the center of a circle is $(2,4)$ and the coordinate of another point on it is $(8,3)$ .

$"So its radius"(r)=sqrt((8-2)^2+(3-4)^2)=sqrt37$

So length of the arc (S) covering $pi/3$ radian on circle will be

$S=rxx"angle"=sqrt37xxpi/3=6.37unit$

A circle's center is at (2 ,4 )(2 ,4 ) and it passes through (8 ,3 )(8 ,3 ). What is the length of an arc covering ( pi ) /3 ( pi ) /3 radians on the circle?