Question

A circle's center is at `(2 ,4 )` and it passes through `(8 ,3 )`. What is the length of an arc covering `( pi ) /3` radians on the circle?

Answer 1

Given that coordinate of the center of a circle is `(2,4)` and the coordinate of another point on it is `(8,3)`.

`"So its radius"(r)=sqrt((8-2)^2+(3-4)^2)=sqrt37`

So length of the arc (S) covering `pi/3` radian on circle will be

`S=rxx"angle"=sqrt37xxpi/3=6.37unit`