A circle's center is at (8 ,7 )(8,7) and it passes through (6 ,5 )(6,5). What is the length of an arc covering (5 pi ) /6 5π6 radians on the circle?

1 Answer
Sudip Sinha
Jan 28, 2016

( 5 sqrt(2) pi ) / 3 5√2π3

Explanation:

Please check my solution here for a detailed explanation.

Solution
Radius r = sqrt( (6 - 8)^2 + (5 - 7)^2 ) = sqrt(2 * 2^2) = 2 sqrt(2) r=√(6−8)2+(5−7)2=√2⋅22=2√2.
Arc length S = cancel(2) sqrt(2) * ( 5 pi ) / ( 3 cancel(6) ) = ( 5 sqrt(2) pi ) / 3 .

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