# A circuit with a resistance of 3 Omega has a fuse melts at 4 A. Can a voltage of 16 V be applied to the circuit without blowing the fuse?

Jul 5, 2016

No

#### Explanation:

$\text{Current"="Voltage"/"Resistance}$

$I = \frac{V}{R}$

$I = \frac{16 V}{3 \Omega} = 5.33 A$

The current ($5.33 A$) is large enough to melt the fuse, so that voltage will melt the fuse.