# A circuit with a resistance of 3 Omega has a fuse with a capacity of 2 A. Can a voltage of 5 V be applied to the circuit without blowing the fuse?

$V = I R$ or $I = \frac{V}{R}$
$I$= $\frac{5}{3}$= $1.6$ $A$
Current in circuit is $1.6$ amperes. Fuse is $2$ $A$. So it will not blow.