A circuit with a resistance of #3 Omega# has a fuse with a capacity of #2 A#. Can a voltage of #9 V# be applied to the circuit without blowing the fuse?

1 Answer
Feb 4, 2016

Answer:

No

Explanation:

This require the application of the standard Ohm's Law expression of #V=I*R#, where #V# is the voltage, #I# is the current and #R# is the resistance

The voltage of #9V# will generate a current of

#I = V/R = 9/3 =3A#

This will blow the fuse so the answer is No.