# A circuit with a resistance of 3 Omega has a fuse with a capacity of 2 A. Can a voltage of 9 V be applied to the circuit without blowing the fuse?

Feb 4, 2016

No

#### Explanation:

This require the application of the standard Ohm's Law expression of $V = I \cdot R$, where $V$ is the voltage, $I$ is the current and $R$ is the resistance

The voltage of $9 V$ will generate a current of

$I = \frac{V}{R} = \frac{9}{3} = 3 A$

This will blow the fuse so the answer is No.