# A circuit with a resistance of 6 Omega has a fuse melts at 5 A. Can a voltage of 18 V be applied to the circuit without blowing the fuse?

$\text{Current" = "voltage"/" Resistance}$.
i.e. $I = \frac{V}{R}$
So current in circuit $I$ = $\frac{18}{6}$ = $3$ $A$.
Fuse capacity is $5$ $A$. So it can be applied safely with out blowing fuse.