# A circuit with a resistance of 6 Omega has a fuse melts at 5 A. Can a voltage of 33 V be applied to the circuit without blowing the fuse?

This law says that the voltage is equal to the product of the resistance and the current. In formula: $V = R \cdot I$.
In your circuit you have a voltage of $33$ V and a resistance of $6$ $\setminus \Omega$. The current is then $33 = 6 \cdot I$ $I = \frac{33}{6} = 5.5$ A.