A circuit with a resistance of #6 Omega# has a fuse that melts at #8 A#. Can a voltage of #42 V# be applied to the circuit without blowing the fuse?

1 Answer
Mar 11, 2018

Answer:

Yes, it can be applied.

Explanation:

First, we need to find the voltage at which the fuse melts.

Thus, we use Ohm's law here, which states that

#V=IR#

The fuse melts at #8 \ "A"# with a resistance of #6 \ Omega#, so we must plug in those values into the equation.

We get:

#V=8 \ "A"*6 \ Omega#

#=48 \ "V"#

So, the fuse will melt at #48 \ "V"# or more.

Since #42 \ "V"<48 \ "V"#, then the fuse will not melt when a voltage of #42# volts is passed through it.

So, a voltage of #42 \ "V"# can be applied on the circuit without blowing the fuse.