Question

A circuit with a resistance of `6 Omega` has a fuse that melts at `8 A`. Can a voltage of `42 V` be applied to the circuit without blowing the fuse?

Answer 1

Yes, it can be applied.

Explanation:

First, we need to find the voltage at which the fuse melts.

Thus, we use Ohm's law here, which states that

`V=IR`

The fuse melts at `8 \ "A"` with a resistance of `6 \ Omega`, so we must plug in those values into the equation.

We get:

`V=8 \ "A"*6 \ Omega`

`=48 \ "V"`

So, the fuse will melt at `48 \ "V"` or more.

Since `42 \ "V"<48 \ "V"`, then the fuse will not melt when a voltage of `42` volts is passed through it.

So, a voltage of `42 \ "V"` can be applied on the circuit without blowing the fuse.