Question

A circuit with a resistance of `6 Omega` has a fuse that melts at `8 A`. Can a voltage of `64 V` be applied to the circuit without blowing the fuse?

Answer 1

No,..Check the reason below

Explanation:

The circuit has resistance of `6Omega`. Applying 64 V to the `6Omega` of the circuit would produce a current of

`I = (64 V)/(6Omega) = 10.7 A`

Except that the circuit has a fuse to protect it. And a current of `8A` melts it...

Thus, use the equation `V=I*R`

The formula tells you that the voltage at which the `6Omega` circuit draws `8A` and melts the fuse is therefore: `48V`.

Thus, u get your answer that any voltage greater than `48V` will blow it up.