# A circuit with a resistance of 6 Omega has a fuse that melts at 8 "A". Can a voltage of 66 "V" be applied to the circuit without blowing the fuse?

By Ohm's law, the current flowing through is given by $I = \frac{V}{R}$.
frac{66 "V"}{6 Omega} = 11 "A" > 8 "A"