A circuit with a resistance of #6 Omega# has a fuse that melts at #8 A#. Can a voltage of #42 V# be applied to the circuit without blowing the fuse?

1 Answer
Jan 14, 2016

Answer:

The current flowing in a circuit can be calculated using Ohm's Law: #V=IR# or #I=V/R#. In this case the current is #7A#, so the fuse is safe.

Explanation:

Ohm's Law relates the current, #I (A)#, electrical potential difference (voltage), #V (V)# and resistance, #R (Omega)# in a circuit.

It is usually stated and remembered as #V=IR#.

Rearranging, #I=V/R = 42/6 = 7 A#

Since the fuse will blow (melt) if the current in the circuit is #8A# and the current is less than that, the fuse will not blow.