# A circuit with a resistance of 8 Omega has a fuse with a capacity of 3 A. Can a voltage of 5 V be applied to the circuit without blowing the fuse?

We can use Ohm`s Law to find the current $I$:
$V = R I$
$I = \frac{V}{R} = \frac{5}{8} = 0.625 A$