# A circuit with a resistance of 8 Omega has a fuse with a capacity of 3 A. Can a voltage of 36 V be applied to the circuit without blowing the fuse?

May 25, 2018

No.

#### Explanation:

Well, we need to find the voltage that the fuse can hold, so we use Ohm's law, which states that,

$V = I R$

where:

• $V$ is the voltage in volts

• $I$ is the current in amperes

• $R$ is the resistance in ohms

So, we get:

$V = 3 \setminus \text{A} \cdot 8 \setminus \Omega$

$= 24 \setminus \text{V}$

Since a voltage of $36$ volts is applied to the circuit, but the fuse only holds $24$ volts, it'll blow up the fuse.