A circuit with a resistance of #8 Omega# has a fuse with a capacity of #5 A#. Can a voltage of #42 V# be applied to the circuit without blowing the fuse?

1 Answer
Jan 26, 2016

Answer:

#No#

Explanation:

Data:-

Resistance#=R=8Omega#

Voltage#=V=42V#

The fuse has capacity of 5A

Sol:-

If we apply voltage #V# across a resistor whose resistance is #R# then the current #I# flowing across it can be calculated by

#I=V/R#

Here we are applying voltage of #42V# across a #8Omega# resistor, therefore, the current flowing is

#I=42/8=5.25# #implies I=5.25A#

Since, the fuse has capacity of #5A# but the current flowing in the circuit is #5.25A# therefore, the fuse will melt. Thus, the answer to this question is #No#.