# A circuit with a resistance of 9 Omega has a fuse melts at 6 A. Can a voltage of 45 V be applied to the circuit without blowing the fuse?

Yes, a voltage of $45 \setminus V$ can be applied to the circuit without blowing the fuse

#### Explanation:

The electric current $I$, flowing through the circuit of resistance $R = 9 \setminus \Omega$ when a voltage of $45 \setminus V$ is applied, is given by Ohm's law

$I = \frac{V}{R}$

$= \frac{45}{9}$

$= 5 \setminus A$

It is given that the fuse melts at current $6 \setminus A$ while the electric current through the circle is less i.e. $5 \setminus A$

Hence, a voltage of $45 \setminus V$ can be applied to the circuit without blowing the fuse