# A container with a volume of 18 L contains a gas with a temperature of 170^o C. If the temperature of the gas changes to 640 ^o K without any change in pressure, what must the container's new volume be?

Jan 14, 2018

The new volume is $= 26 L$

#### Explanation:

Apply Charles' Law

$\text{volume"/"Temperature"="Constant}$, $\text{At constant pressure}$

${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$

The initial volume is $= {V}_{1} = 18 L$

The initial temperature is ${T}_{1} = 170 + 273 = 443 K$

The final temperature is ${T}_{2} = 640 K$

The final volume is

${V}_{2} = {T}_{2} / {T}_{1} \cdot {v}_{1} = \frac{640}{443} \cdot 18 = 26 L$