A container with a volume of $18 L$ contains a gas with a temperature of $250^o C$ . If the temperature of the gas changes to $360 ^o K$ without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-02-16T06:49:09

The new volume is $=12.39L$

We apply Charles' Law

$V_1/T_1=V_2/T_2$

$V_1=18L$

$T_1=250+273=523K$

$T_2=360K$

$V_2=T_2/T_1*V_1$

$=360/523*18=12.39L$

A container with a volume of 18 L18 L contains a gas with a temperature of 250^o C250^o C. If the temperature of the gas changes to 360 ^o K360 ^o K without any change in pressure, what must the container's new volume be?